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x^2=7x+28
We move all terms to the left:
x^2-(7x+28)=0
We get rid of parentheses
x^2-7x-28=0
a = 1; b = -7; c = -28;
Δ = b2-4ac
Δ = -72-4·1·(-28)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{161}}{2*1}=\frac{7-\sqrt{161}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{161}}{2*1}=\frac{7+\sqrt{161}}{2} $
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